Confirmed Errata – Study Guide for FE Electrical and Computer CBT Exam – Third Edition
Corrections – Problems Section:
Problems 2.2 e) to 2.2 i) scenario statement shall have
A = {1, 3, 5, 7, 10}
Problem 8.4 a) Second graph represents y(t) not h(t).
Problem 9.1 c) Electron and hole concentrations of a semi-conductor wafer at equilibrium are found to be n = p = 2 x 10¹⁰ m¯³….
Problem 10.2 e) Option B) 23.5∠4.5°Ω
Problem 10.4 g) A single-phase 240V power source is feeding a 20A, unity power factor load with a #10AWG copper conductor in a steel conduit such that R = 1.2Ω/1000ft (circuit reactance can be ignored). One-way length of this circuit is 500 feet. Calculate the approximate total voltage drop of given circuit.
Option D) 24V
Problem 11.1 i) Q₂ = 15 x 10¯⁹C
Problem 13.6 e)
Option A) 5µs Option B) 6.66µs
Option C) 10µs Option D) 20µs
Problem 17.4 j) and Problem 17.4 k)
Starting point for graph traversal is ‘O’
Corrections – Solutions Section:
Solution 1.3 e) …. According to the definition, {(1, b), (1,c), (1,d)} is not a function because input 1 is related to multiple outputs.
Solution 1.1 c) x = -2 is an invalid solution because logarithm of negative real number is undefined.
Solution 1.4 l) …. Eccentricity of a hyperbola is given by….
It is a long established fact that a reader will be
Solution 5.2 b) ???? required = 6 x 10¯³
Solution 8.1 f) CORRECT ANSWER – C
Reconstructed signal frequency will be 50Hz with a positive phase angle (due to the positive sign inside the mod operator) as shown below:
x'(t) = cos(2????(50)t + θ)
x'(t) = cos(2????(50)t + θ)
Solution 8.3 l)
Y(z) (1 + z¯¹ + 2z¯²) = X(z) (1 + z¯¹ + 2z¯²)
Solution 9.2 a)
iD1 = (5V – 1V) / 1kΩ = 4mA
Solution 9.5 g)
R₁ = (6V – 1V) / 1mA = 4.8kΩ ≅ 5kΩ
Solution 10.4 g)
Total voltage drop (2-way) in a single-phase system with unity power factor and negligible circuit reactance can be calculated using the following formula:
VD = (2 x L x R x I) / (k x 1000)
VD = Voltage Drop – ?
L = 1-way circuit length = 500 ft
R = Conductor resistance = 1.2 Ω/ft
I = Load current = 20A
k = 1.0 for single-phase AC circuit
VD = (2 x 500 x 1.2 x 20) / (1 x 1000) = 24V
Solution 10.6 l) CORRECT ANSWER: 297 Nm
Pm = T???? = T x (2????/60) x n
T = Pm / [(2????/60) x n] = 297 Nm
Solution 12.1 c) CORRECT ANSWER: (s + 2)² / [s(s + 4)]
T = [(s + 4) + (s + 3)] / [s(s + 4)] = (s + 2)² / [s(s + 4)]
Study Guide for FE Electrical and Computer CBT Exam Second Edition Errata –
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