###### Confirmed Errata for ‘Study Guide for Fundamentals of Engineering (FE) Electrical & Computer CBT Exam’

### Corrections in Problems section:

Problem 1.1 b) Which of the following techniques is not used for **corrosion prevention**?

(D) Options A, B and C provide **corrosion prevention**

Problem 1.1 d) Units for activation energy should be J/mol in this question.

Problem 1.2 e) Calculate the magnetic permeability …. at a distance of **50cm** perpendicular to the wire.

Problem 1.4 f) Students are measuring **heat capacities** of three different samples of same liquid. Sample 1 is 1kg, sample 2 is 2kg and sample 3 is 3kg. Which of the following options correctly indicates their **heat capacities**?

Problem 2.3 a)

(A) **22.6 x 10 ^{6}**

Problem 2.4 c)

(D) **500J**

Problem 3.1 d)

(D) **1.7A**

Problem 3.5 c) Capacitive reactance in the problem shall be *-j100Ω*

(D) **0.14 A phase angle 11.3⁰**

Problem 4.2a) *The circuit diagram incorrectly shows inductance on resistor and resistance on inductor.*

Problem 4.2e)

(B) **0.707**

(C) **500**

Problem 4.2f)

(D) **1000 rad/s**

Problem 4.4e)

(D) Poles 1st order @ 0.2, 2nd order @ 0, Zero – none, Gain = **20dB **

Problem 5.1a)

(C) Output function should be **16** for 2<t<6** **

Problem 5.1c)

(D) ** **1 – cos(t) 0 < t ≤ π,** 1- cos(t) **π < t ≤ 2π

Problem 6.3b)

(D) Ic = **1.13mA**, Vce = 1.3V

Problem 6.3e)

(C) Ie = 3.2mA, Vec = **5.1V**

Problem 6.3f)

(D) Ie = 1.5mA, Vec = **2V**

Problem 6.4b) Emitter voltage shall be *6V (assume k=0.5mA/V^2 and Vt = 1V)*

(B) **Saturation**

(C) **Triode**

Problem 6.4e) 10kΩ collector resistor source voltage shall be *10V*

Problem 6.6 e) Which of the following devices **can** be used for **resistance** measurements?

(B) **Strain Gage**

(D) **Options A, B and C are correct**

Problem 7.1 c) *Units for options should be ‘VA’*

Problem 7.1 g)

(A) **5 – 2j Ω**

Problem 7.3 c)

(A) **7%**

Problem 7.6 c) Missing information – *V _{rms} = 400V and frequency = 60Hz.*

Problem 7.6 d) A three phase power utility provides 75 kVA at 0.85 lagging and 35 kVA at 0.75 **lagging** power factor…..

Problem 7.6 e) A balanced 3-phase ……. Y-connected load that consumes **375kW** at 0.85 power factor lagging ….

Problem 9.2 e) H(s) = 100s / (s^{2} + 150s + **5000**)

Problem 9.6 a) y” + **3**y’ + 2y = 2u(t)

Problem 10.1 d) A message signal …. using a carrier signal of 50sin2π(**4000t**). Calculate the modulation index.

Problem 10.3 b) Calculate the minimum bandwidth required to transmit a pulse code modulated message m(t), with M(f) = 0 for f >= 100 Hz using **256** quantization level.

Problem 11.2 a)

(C) **Star**

### Corrections in Solutions section:

1.4 e) **Heat capacity** is directly proportional to amount of material. Sample # 3 will have the higher **heat capacity** because it contains the largest amount of substance being tested. Sample # 1 has the least amount of substance therefore it will have the lowest **heat capacity**.

2.3 a) Since **Q = CV** this implies that **V = Q/C**

2.4 c) Therefore energy stored = **500 J**

3.5 c)I = 0.14__/11.3◦__ A

4.2 e) Q = **R/(Lω _{0}) **

Therefore Q = **500/707=0.707**

4.4 e) H(s) = 10 / [s^{2} (s/0.2 + 1), |gain| = 20log(10) = **20 dB**

Therefore Q = **500/707=0.707**

5.1 c) Region # 3 f(t) =** 1- cos(t) **π < t ≤ 2π

6.6 e) Wheatstone bridge, RTD and **Strain Gage** can be used to measure **resistance**.

7.1 g) Zload = Zthevenin* = (5 + 2jΩ)* = **5 – 2jΩ**

7.2 g) ~~Z~~_{line} = 1 + jΩ

7.3 c) Vp/a = 427.8V, V.R = (427.8 – 400)/400 = **7%**

7.6 c) Solving for Ɵ_{2} gives **8.337⁰**, cos(Ɵ_{2}) = **0.989**

7.6 e) C_{1φ} = [375000(tan31.87◦ – tan18.19◦)] / [(2π)(60)(120)^{2}] = 6.7mF ≈ 7mF

10.1 d) Modulation Index = signal amplitude / carrier amplitude

12.5 h) *1st clock cycle column should read Q _{0} and 2nd column as Q_{1}*